Question 3 Suppose we set θ0=−1,θ1=0.5. What is hθ(4)?

Answer:

Letting x = 4, we have h_{θ}(x)=θ_{0}+θ_{1}x = -1 + (0.5)(4) = **1**

Question 3 Suppose we set θ0=−1,θ1=0.5. What is hθ(4)?

Answer:

Letting x = 4, we have h_{θ}(x)=θ_{0}+θ_{1}x = -1 + (0.5)(4) = **1**